New Register here for RBI, SEBI & NABARD strategy workshop! April 9 at 7 PM

    Question

    A right circular cone has a height that is double its

    radius, and its volume is measured at 2,250π cm³. If the radius is reduced to one-third and the height to half of their original sizes, what would be the new volume of the cone? 
    A 225π cm³ Correct Answer Incorrect Answer
    B 375π cm³ Correct Answer Incorrect Answer
    C 125π cm³ Correct Answer Incorrect Answer
    D 250π cm³ Correct Answer Incorrect Answer

    Solution

    Let the radius of right circular cone be 'R' cm. So, height of cone = '2R' cm Volume of a right circular cone = (1/3) X π X (radius) 2 X height So, (1/3) X π X R2 X 2R = 2,250π Or, R3 = 3,375 Or, 'R' = 15 cm Height of cone = 2 X 15 = 30 cm New radius of cone = (15/3) = 5 cm New height of cone = (30/2) = 15 cm So, required volume = (1/3) X π X 52 X 15 = 125π cm3

    Practice Next

    Relevant for Exams: