Question
The radius of the base of a
cylindrical tank is 5 metres. If eight times the sum of the areas of its two circular faces is four times the area of its curved surface, then find the difference between its radius and its height. {Take π = 22/7}Solution
ATQ,
Area of two circular faces = 2πr2 Curved surface area (CSA) = 2πrh Equation = 8×(2πr2) = 4×(2πrh)
Simplify: 16πr2 = 8πrh ⟹ 2r = h Substitute r = 5: h = 2r = 2×5 = 10metres Find the difference = h − r = 10 − 5 = 5metres
More Mensuration Questions
The question below is based on the given series I. The series I satisfy a certain pattern, follow the same pattern in series II and answer the questions...
6, 5, 40, 32, 249, 240
60000 2400 120 8 0.8 ?
...25, 200, 40, ?, 64, 512
1 2 9 ? 65 126
...27   44    63    86   ?      146
7    7       14    42   ?     840
...59, 170, 301, 452, ?, 814
If 16 15 26 69 260 x,
Find 75% of x+ x
29    51    95    183    ?     711
