Total surface area of a right circular cylinder is 792π cm2. If the height of the cylinder is 3 cm less than its diameter, then find the diameter of base of the cylinder.
Let the diameter of the given cylinder be '2x' cm So, height of the cylinder = (2x - 3) cm So, radius of the cylinder = 2x ÷ 2 = 'x' cm Total surface area of the cylinder = 2πr(r + h) {Where 'r' and 'h' is radius and height of the cylinder} ATQ; 792π = 2 X π X x X {x + (2x - 3)} Or, 396 = x X (3x - 3) Or, 132 = x X (x - 1) Or, 132 = 12 X 11 So, x = 12 So, diameter of the base of the cylinder = 12 x 2 = 24 cm
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? + (35)² = (130)² - (45)² - 2850
