The length of a rectangle is 8 cm more than its breadth. If the area of the rectangle is 192 cm², determine the perimeter of the rectangle.
ATQ,
Let the breadth of the rectangle be 'x' cm. Then, the length of the rectangle will be 'x + 8' cm. According to the given conditions, x(x+8) = 192 Or, x2 + 8x − 192=0
Factoring the quadratic equation, x2 +16x − 8x − 192 = 0 Or, x(x+16) - 12(x+16) = 0 Or, (x-12)(x+16) = 0 So, x = 12 or x = −16 (not possible)
Breadth of the rectangle = 12 cm Length of the rectangle = 12 + 8 = 20 cm Perimeter of the rectangle = 2(12+20) = 2×32 = 64 cm
Find the Value of 1/8 + 999 (71/72) × 9
7(3/6) of 534 + 262 = 61800 - ?
82.3 × 644.7 × 723.4 × 815.85 = 72?
1200% of 18 + √1600 + 62 = ?2 + (90 of 0.4)
40% of (362 ÷ 0.05) = ?
16/15 of 21/28 of 321.5 = ?
3 √(432 – 13 + 9 × 32) = ?
5234 + 1562 + 2359 − 5893 = 3167 − 121 + ?3
((0.1)3+ (1.8)3+ (1.1)3- 0.3 ×1.8 ×1.1)/((0.1)2+ (1.8)2+ (1.1)2- (0.18)- (...