Original perimeter of rectangular field = 2 × (60 + 40) = 200 m Increased length of rectangular field = 1.25 × 60 = 75 m Increased breadth of rectangular field = 1.45 × 40 = 58 m Increased perimeter of rectangular field = 2 × (75 + 58) = 266 m Required percentage increase = {(266 – 200)/200} × 100 = 33%
255 × 8 + 386 × 5 =? % of 7940
45% of 360 - 160 + ? = √324
56 ÷ 14 × 4 – 316 + ? 2 = 100
323 × 15 + (?)² = 4989
(√1024 + √324)% of 780 = ?% of 260
2197 1/3 + 30% of 1800 = ?× 343 1/3
2 X 25 + (30% of 80) ÷ (10% of 120) = ?
(42% of 1500 + 170) ÷ 4 = ?2 - 52
84% of 800 + 70% of 640 = 14 × ?
√4096 + √3249 = (?)2