Consider a rectangle where the length to breadth ratio

Solution

Let the length and the breadth of the rectangle be '4a' cm and '3a' cm ATQ, Area of the rectangle = length X breadth 48 = (4a X 3a) Or, a² = (48/12) = 4 So, 'a' = ±2 But length can't be negative, so 'a' = 2. Length of diagonal of the rectangle = {(length) ² + (breadth) ² }^1/2 Length of the diagonal of the rectangle = {(4a) ² + (3a)²}^1/2 = (25a²) ^1/2 = 5a = 10 cm So, side of the square = length of diagonal of rectangle = 10 cm Therefore, perimeter of the square = (4 X 10) cm = 40 cm