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Let the parallel sides of trapezium be 2a and 5a cm respectively. Area of trapezium = (1/2) X (sum of parallel sides) X (distance between parallel sides) So, (1/2) X (5a + 2a) X 24 = 1,344 Or, 7a X 12 = 1,344 Or, 7a = 112 So, 'a' = 16 Therefore, required difference = 5a - 2a = '3a' = 3 X 16 = 48 cm
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