Question
A circular field, which covers an area of 1386 square
meters, is planned to be enclosed by a compound wall that rises to a height of 3 meters. The wall is designed to be thin, with its thickness considered negligible. Calculate the surface area of one side of this compound wall.Solution
Let the radius of the circular field = 'r' metres Then, area of the field = π X r2 = (22/7) X r2 = 1386 So, r2 = 1386 X (7/22) = 441 So, r = √441 = 21 {Since, radius cannot be negative} Circumference of the circular field = 2 X (22/7) X 21 = 132 metres So, surface area of one side of the compound wall = 2πr X height = 132 X 3 = 396 m2
(?)2 + 6.113 = 25.92 – 19.03
(11.75)2 - 49.99% of 120 - ? = (8.23)2Â
70.008% of 399.98 + ?% of 399.999 = 80.105% of 599.998
 ?² × 55% of (29 + 32 - 41) = 41.66% of 216 + 9
22.03 × 6.97 + 19.01 – 16.02 = ?
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
3.934 - 124.07 + 35.94 + 12.83 of 4.85 - 84.76 ÷ √26 = ?3Â
24.75% of 20.125% of 30.05% of 2196.06 = ?Â
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
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