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Let's assume the height and base of the parallelogram is '14x' cm and '9x' cm, respectively. ATQ; 14x X 9x = 1134 Or, 126x2 = 1134 Or, x2 = 9 Or, x = 3 (since, length cannot be negative therefore, we will take the positive root only) Required difference = 14x - 9x = 5x = 5 X 3 = 15 cm Hence, option a.
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