Area of field = 3456/8 = 432 cm2 So, (x + 4)(x – 2) = 432 Or, x2 + 2x – 440 = 0 Or, x2 + 22x – 20x – 440 = 0 Or, x(x + 22) – 20(x + 22) = 0 Or, (x + 22)(x – 20) = 0 So, x = 20 Perimeter of the field = 2 × {(20 + 4) + (20 – 2)} = 84 metres Desired cost = 84 × 15 = Rs. 1260
For the cumulative distribution function
the upper quartile point is
For the study purpose, the mean of the observations is 148 gm and standard deviation is 17.4 gm. Approximately, the coefficient of variation equals to:
Which option is incorrect?
Which of the following is NOT a way of the sampling?
The interquartile range excludes ___ of the values.
If the difference between the rank of the 4 observations are 2.5, 0.5, -1.5, -1.5, then Spearman's rank correlation coefficient equals to:
For a random variable x, the central moments (µi) of all order exist. The square of (2j + 1)th moment (µ22j+1) is
If mean and median of the distribution are 12 and 21, then the distribution
If A,B and C are arbitrary events, then P(A ∩ B ∩ C) equals to:
