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Volume of the tank = l × w × h = 12 × 10 × 8 = 960 m³. Water in the tank = 60% of 960 = 0.6 × 960 = 576 m³. Volume of the cylindrical pipe = πr²h = (22/7) × 0.5² × 7 = (22/7) × 0.25 × 7 = 5.5 m³. Total water after submerging = 576 + 5.5 = 581.5 m³. Percentage filled = (581.5 / 960) × 100 ≈ 60.6%.
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