Question
A rectangular tank has a length of 12 m, width of 10 m,
and height of 8 m. It is filled with water up to 60% of its capacity. A cylindrical pipe with radius 0.5 m and length 7 m is submerged entirely in the tank. Find the percentage of the tank filled after submerging the pipe.Solution
Volume of the tank = l × w × h = 12 × 10 × 8 = 960 m³. Water in the tank = 60% of 960 = 0.6 × 960 = 576 m³. Volume of the cylindrical pipe = πr²h = (22/7) × 0.5² × 7 = (22/7) × 0.25 × 7 = 5.5 m³. Total water after submerging = 576 + 5.5 = 581.5 m³. Percentage filled = (581.5 / 960) × 100 ≈ 60.6%.
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