Volume of the tank = πr²h = (22/7) × 14² × 10 = (22/7) × 196 × 10 = 6160 m³. Volume of water in the tank = 75% of 6160 = 0.75 × 6160 = 4620 m³. Volume of each smaller container = πr²h = (22/7) × 7² × 5 = (22/7) × 49 × 5 = 770 m³. Number of smaller containers required = 4620 / 770 = 6. Correct option: c
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