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Area of equilateral triangle = (√3/4) X side2 Let the side of the given triangle be 'a' cm. ATQ; 432√3 = (√3/4) X a2 Or, 432 X 4 = a2 So, 'a' = ± 24√3 Since, side cannot be negative, a = +24√3 Height of equilateral triangle = (√3/2) X side So, height of the given triangle = (√3/2) X 24√3 = 36 cm So, length of each side of the square = 36 cm So, perimeter of the square = 36 X 4 = 144 cm And perimeter of the triangle = 24√3 X 3 = 72√3 cm So, required difference = 144 - 72√3 = 72(2 - √3) cm
24.912% of ? – 35.06% of 199.91 = 19.97% of 224.89
25.04 × 22.03 + 383.92 ÷ ? + 23.78% of 1499.98 = 926.08
70.008% of 399.98 + ?% of 399.999 = 80.105% of 599.998
1560.182 ÷ √168 + √143 * √224 – 4649.87 ÷ 30.883= ?
(?)2 + 8.113 = 28.92 – 73.03
139.88% of 119.89 + 1451.89 ÷ 6.01 - √196.01 = ? ÷ 3.01 + 215.98
15.2 x 1.5 + 258.88+ ? = 398.12 + 15.9
7.9% of 174.92 + 24.99 - 131.99 ÷ 11.95 × 2.98 = ?
19.97% of 3/5 ÷ (1 ÷ 74.99) = ?