Question
A solid metallic sphere of diameter 30 cm is melted and
recast into a right circular cone having diameter of the base equal to 15 cm. What is the height of the cone?Solution
Radius of the sphere = 30 ÷ 2 = 15 cm Volume of the sphere = 4/3 X 22/7 X 15 X 15 X 15 cm3 Let the height of the cone be 'h' cm. Now, volume of the sphere = volume of the cone So, 4/3 X (22/7) X 15 X 15 X 15 = 1/3 X 22/7 X (15/20 X (15/2) X h Or, 'h' = 4 X 2 X 2 X 15 So, 'h' = 240 Required height = 240 cm
2660.03 ÷ 94.98 x 59.9 = ? + 20.32
What approximate value will come in place of question (?) in the following given expression? You are not expected to calculate the exact value.
...
Find the approximate value of Question mark(?). No need to find the exact value.
(519.79 ÷ 10.03) × (47.98 ÷ 6) + √(63.94) × 4.04 = ?
...447.79 ÷ √(√2400) + 30.94 × 6.07 – 5.08 × 21.96 = ?
1131.98 + ? – 1125.04 = 1364.93 – 1168.01
11.11% of 1800.89 + 34.89 X 10.99 - 500.50 = ?
(3/7 of 1049.88 + 44.95% of 799.79) ÷ (√168.89 + 24.77% of 400.11) = ?
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
If a:(b+c) =3:9 and c:(a+b) =10:14 then find the value of b:(a+c)?
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