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Let the length and the breadth of the rectangle be 6x metres and 5x metres respectively.
Area of the rectangle = length X breadth
ATQ,
6x X 5x = 120
Or, x 2 = 4
Or, 'x' = 2
So, the perimeter of the rectangle = 2 X (length + breadth)
So, 2 X (2 X 6 + 2 X 5) = 2 X 22 = 44 metres
So, the perimeter of the square = 44 + 20 = 64
So, side of the square = (64/4) = 16 metres
So, the radius of the circle = (16/8) X 7 = 14 metres
So, required area = π X radius 2 = (22/7) X 14 X 14 = 616 m 2
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