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ATQ,
Outer radius of the pipe = 4.8 + 2.5 = 7.3 cm
Volume of the hollow pipe = π × height × [(outer radius)² - (inner radius)²]
= (22/7) × 20 × (7.3² - 4.8²)
= (22/7) × 20 × (53.29 - 23.04)
= (22/7) × 20 × 30.25
= 1,290 cm³
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