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ATQ,
Outer radius of the shell = 9.5 + 4 = 13.5 cm
Volume of the shell = π × height × [(outer radius)² - (inner radius)²]
= (22/7) × 10 × (13.5² - 9.5²)
= (22/7) × 10 × (182.25 - 90.25)
= (22/7) × 10 × 92
= 1,314.29 cm³ or 1314 cm³
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