If the altitude of an equilateral triangle is 9 cm then find out its area?
Altitude of equilateral triangle = 9 cm √3/2 × side = altitude side = (9×2)/√3 = 6√3 cm Area of equilateral triangle = √3/4 × side² = √3/4 × 6√3 × 6√3 = 27√3 cm²
If ∆ ABC~∆ FDE such that AB = 9 cm, AC = 11 cm, DF = 16 cm and DE = 12 cm, then the length of BC is:
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