A cylindrical tub of radius 8cm contains water up to a depth of 15cm. A spherical iron ball is dropped into the tub and thus the level of water is raised by 4.50cm. What is the diameter of the iron ball?
Volume of ball = volume raised water = π (8)2 4.50 Now, 4/3 πr3 = π × 64 × 4.50 r3 = 16 x 4.50 x 3 = 216 r = 6 cm Diameter of iron ball = 2(6cm) = 12 cm
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