A 220-litre mixture contains petrol and water, only in ratio 6:5, respectively. How much water should be added in the mixture so that the quantity of water becomes 50% of quantity of resultant mixture?
Quantity of water in the initial mixture = 220 × (5/11) = 100 litres Quantity of petrol in the initial mixture = 220 × (6/11) = 120 litres Since, we’re not adding petrol, 120 litres of petrol will represent 50% of the new mixture. So, total quantity of resultant mixture = 120 ÷ 0.5 = 240 litres Quantity of water to be added = 240 – 220 = 20 litres
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