Question
360 ml of mixture βAβ contains milk and water in the
ratio 5:7 respectively. If the quantity of milk in mixture βBβ is 25.5% more than that in mixture βAβ and is 25% of the total quantity of mixture βBβ then find the total quantity of mixture βBβ.Solution
Quantity of milk in mixture βAβ = 360 Γ 5/12 = 150 ml Quantity of water in mixture βAβ = 360 - 150 = 210 ml Quantity of milk in mixture βBβ = 1.225 Γ 150 = 188.25 ml Total quantity of mixture βBβ = 188.25/0.25 = 753 ml
(13.156)2 + (3.945)2 + (5.903)3 = ?
β784 Γ 3 + (713.99 Γ· 6.98) = ?% of 619.99
1726Β 1/3 + 40% of 1849.889 + 15.12 Γ 18.25 = ?
2470.03 Γ· 64.98 x 39.9 = ? + 20.32
583.9 + 1519.98 - 445.21 = 1150.011 + ?
2380.03 Γ· 84.98 x 39.9 = ? + 15.32
If the length of one side of a rhombus is 16cm then find its surface area. (use β 3 = 1.732)
5466.97 - 3245.01 + 1122.99 = ? + 2309.99
? = (5.8)2 + (8.9)2 + (4.7) 2 + 24.7% of 20