A container has only two types (P and Q) of oil in the ratio 3:2 respectively. When 90 litre of oil Q is added to the containerthe quantity of oil P becomes 25% of that of oil Q. Find the capacity of the containerif it becomes full after addition of 90 litre of oil.
Let the quantity of oil in the containerbe 3x and 2x litres respectively. According to the question, => 3x = 0.25 × (2x + 90) => 2.5x = 22.5 => x = 9 Total capacity of the container= 3x + 2x + 90 = 135 litres.
I. p2 - 19p + 88 = 0
II. q2 - 48q + 576 = 0
I. 20x² - 93x + 108 = 0
II.72y² - 47y - 144 = 0
I. 2x2– 25x + 33 = 0
II. 3y2+ 40y + 48 = 0
I. 27x6- 152x3+ 125 = 0
II. 216y6- 91y3+ 8 = 0
I.√(3x-17)+ x=15
II. y+ 135/y=24
I. 8a2 – 22a+ 15 = 0
II. 12b2 - 47b + 40=0
In each of these questions, two equations (I) and (II) are given.You have to solve both the equations and give answer
I. x2 – ...
I. 27x6-152x3+125=0
II. 216y6 -91y3+8=0
I. x2 - 20x + 96 = 0
II. y2 - 23y + 22 = 0
I. y² - 7 y – 18 = 0
II. x² + 10 x + 16 = 0