Question
One alloy of steel contains 74% Iron and 26% carbon.
Another alloy contains 81% Iron and 12% carbon. Later, they are mixed, so that the mixture contains 20% of carbon. What percent of Iron will it contain?Solution
The alloy should be mix in the ratio of 4:3 Now, 
Difference of 81-74 = 7 7 is divided in the ratio of 4:3 7 × `3/7` = 3% So required iron% = 74+3 = 77%
Simplify the following expression:
3.5 x 0.5 x (4.4 – 0.625 ÷ 1.5625)
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