165 litres of Mixture ‘A’ (water + alcohol) contains 30% water and remaining alcohol while 119 litres of mixture ‘B’ (milk + water) contains 20 litres more milk than water. Find the sum of quantities of water in both the given mixtures.
Quantity of water in mixture ‘A’ = 165 × 0.30 = 49.5 litres Let the quantity of water in mixture ‘B’ = ‘x’ litres Then, quantity of milk in mixture ‘B’ = (x + 20) litres So, x + (x + 20) = 119 Or, 2x + 20 = 119 Or, x = (119 – 20) ÷ 2 Or, x = 49.5 Therefore, quantity of water in mixture ‘B’ = x = 49.5 litres So, sum of quantity of water in both the mixtures = 49.5 + 49.5 = 99 litres.
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