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Let the quantity of milk in mixture ‘A’ = ‘y’ litres Then, quantity of water in mixture ‘A’ = (y + 32) litres So, y + y + 32 = 128 Or, 2y = 128 – 32 = 96 Or, y = 96/2 = 48 So, quantity of milk in mixture ‘A’ = 48 litres And, quantity of water in mixture ‘A’ = 48 + 32 = 80 litres Quantity of milk in 25% of mixture ‘A’ = 48 × 0.25 = 12 litres Quantity of water in 25% of mixture ‘A’ = 80 × 0.25 = 20 litres So, quantity of milk in the jar = 12 + 70 = 82 litres Quantity of water in the jar = 80 + 20 = 100 litres So, required percentage = (82/100) × 100 = 82%
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