Question
The container has 60 liters of mixture of alcohol and
water in the ratio of 3:1. If 28 liters of mixture is replaced by water, then what is the ratio of the quantity of alcohol to water in the final mixture?Solution
Alcohol in the container = (3/4) × 60 = 45 liters Water in container = 60 - 45 = 15 liters Alcohol in 28 liters of mixture = 28 × (3/4) = 21 liters Water in 28 liters of mixture = 28 – 21 = 7 liters Required ratio = (45 – 21) : (15 – 7 + 28) = 2:3
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