A mixture contains oil and water in the ratio 7:5. When 70% of this mixture is replaced with 153 litres of water, the ratio becomes 8: 13. Than, what will be the quantity of original mixture?
Ratio of oil and water = 7 : 5 (Initially) Ratio of oil and water = 8 : 13 (After adding 153 litres water) Equating oil from the mixture:- Ratio of oil and water = 56 : 40 (Initially) Ratio of oil and water = 56 : 91 (After adding water) 51 units = 153 litres 1 units = 3 litres Initially quantity of mixture = 96 x 3 = 288 30% -- 288 litres therefore, orginal mixture will be = 100 % --- 960 litres
What is the remainder when (x²⁷ + 51) is divided by (x + 1)?
Rs 625 is to be divided among A, B and C so that A gets 2/9 of B’s share and C gets 3/4 of A’s share. Share of C is:
There are five numbers A, B, C, D and E. The ratio between the numbers of B and D is (y+1) : 3 respectively. The number C is 12.5% more than the number ...
A five digit number 2A78B, is divisible by 55. What is the difference between the maximum and minimum possible value of (A+B)?
If a = 12, b = 23, c = 34, ............... z = 2627. How many zeros are formed after multiply a × b &t...
If the first term is 125 and the common ratio is 3/5, then what will be the fourth term of the geometric progression (G.P)?
Which one of the following numbers is divisible by 11?
When a number is divided by 114, remainder is 82. What will be the remainder when the cube of the number is divided by 19?