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In a mixture of milk and water, the quantity of water is 50% more than the quantity of milk. Let’s assume the initial quantity of milk is 2y. quantity of water initially = (100+50)% of 2y = 150% of 2y = 3y If 16 liters of water is mixed into it, then the quantity of milk will be 34% less than the quantity of water. 2y/(3y+16) = 66/100 y/(3y+16) = 33/100 100y = 99y+528 y = 528 Difference between the initial quantity of milk and water in the mixture = (3y-2y) = y = 528
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Match List-I with List-II :
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