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Two bottles namely P and Q contained pure milk and pure water in the quantity of (a+135) litre and (a-10) litre respectively. If 40% and 36% from bottle P and Q is taken out and poured into bottle R and (a/5) litre of milk is added into it such that the ratio of the quantity of milk and water in the bottle R will be 5:2 respectively. [(a+135) of 40% + (a/5)] / [(a-10) of 36%] = 5/2 [(a+135)x0.4 + 0.2a] / [(a-10)x0.36] = 2.5 [0.4a+54+0.2a] / [0.36a-3.6] = 2.5 [0.6a+54] / [0.36a-3.6] = 2.5 [0.6a+54] = 2.5x[0.36a-3.6] 0.6a+54 = 0.9a-9 54+9 = 0.9a-0.6a 0.3a = 63 Value of ‘a’ = 210
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