In a container, there are 120 liters of a mixture comprising Soda and water in a ratio of 5:3, respectively. If 'y' liters of the mixture are withdrawn from the container, resulting in a difference of 24 liters between the quantity of Soda and water left in the container, what is the value of 'y'?
Let the quantity of Soda and water left in the glass be 5b litres and 3b litres, respectively ATQ, 5b – 3b = 24 Or, 2b = 24 Or, b = 12 Therefore, quantity of mixture left in the jar = 5b + 3b = 8b = 96 litres Therefore, quantity of mixture taken out = 120 – 96 = 24 litres Or, y = 24
17.5% of 400 – 24% of 150 = ?
3.3 Times 2/27 of 40% of 364=?
2/5 of 3/4 of 7/9 of 14400 = ?
?2 + 114 - 48 ÷ 2 × 5 = 163
(3984 ÷ 24) x (5862 ÷ 40) = ?
2916 ÷ 54 = ? + 27
[(4√ (7) +√ (7))× (7√ (7) + 6√ (7))] - 87 = ?
...95% of 830 - ? % of 2770 = 650
125 ÷ 5 + 14 × 4 = ? + 72 ÷ 4 – 35