In a 600-gram mixture, the proportion of Component A to Component B is 3:7. If you add 20 grams of Component A and 80 grams of Component B to the mixture, what will be the new ratio of Component B to Component A in the resultant mixture?
ATQ, Quantity of Component A in mixture = (3/10) × 600 = 180 grams Quantity of Component B in mixture = 600 – 180 = 420 grams According to question, Desired ratio = (420 + 80):(180 + 20) = 5:2
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