Question
In mixture 'X,' there are (4a + 20) liters of Juice and
the remaining 20% consists of Soda.When mixture 'X' is combined with mixture 'Y,' which contains (a - 4) liters of Lime and the rest is 70% Sugar syrup the resulting mixture has a ratio of Soda to Lime equal to 3:2. Calculate the quantity of Sugar syrup in mixture 'Y.Solution
ATQ, We can say that, Total quantity of mixture 'X' = {(4a + 20)/0.8} = (5a + 25) Liters Quantity of Soda in mixture 'X' = (5a + 25) - (4a - 20) = (a + 5) Liters According to the question, {(a + 5)/(a - 4)} = (3/2) Or, 2a + 10 = 3a - 12 Or, 'a' = 22 Quantity of Lime in mixture 'Y' = a - 4 = 22 - 4 = 18 Liters Quantity of Sugar Syrup in mixture 'Y' = (18/0.3) × 0.7 = 42 Liters
(44.79 × 74.21) ÷ (11.862 – 33.12) + 37.48% of ? = 180.23
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
(?)2 + 6.113 = 25.92 – 19.03
8 × 1099.95 ÷ 20.03 + 187.95 = ? × 3.96
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
16.22 × 12.99 + 142.15 = ?
6401.23 × `1 3/4` - 352.87 × ? = 10443.789
A sum of ₹60,000 is invested at a compound interest rate of 'x%' per annum, compounded annually, and grows to ₹75,264 in 2 ye...
620.15 + 1279.98 + ? × (4.79)2 = 149.95% of 1600.14
68.98 × 41.03 – (12.33)² + 15.78% of 8398.87 = ? – 40.22