Question
40 liters of milk are kept in a container. 4 liters were
removed and replaced with water. This procedure was performed two more times. How much milk does the container now hold?Solution
we know . remaining milk in the container = Original amount × [1- amount taken out /original amount] ⁿ = 40[1-4/40] ³ =40[9/10] ³ =40 × 729 /1000 =29.16 liters
More Mixture Questions
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
24.45% of 14.99% of 14999.78 + 159.80 = ?% of 1999.78
15.78% of (287 + 302) + 12³ = ?% of 170 + 8 × 14 + 3²
? = 65.78² ÷ (5.01⁵ + 7.02 × 33.33) + 33.33% of (290.88 × 23.09)
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
1784.04 - 483.98 + 464.98 ÷ 15.06 = ?3
? = 54.89 × 270.08 ÷ 135.17 + 464.35 ÷ 29.03
233.98 + 73 × √35.95 - ? = 275.94 ÷ 3.99
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