A certain mixture consists of oil and water, with the water content exceeding that of oil by 20%. When 70 ml of oil and 60 ml of water are introduced into the mixture, the ratio of oil to water in the new mixture becomes 11:12. Can you determine the original quantity of water in the mixture?
We can say that let initial quantity of oil in the mixture be ‘a’ ml Initial quantity of water in the mixture = 1.2 × a = 1.2a ml According to question, (a + 70)/(1.2a + 60) = 11/12 12a + 840 = 13.2a + 660 1.2a = 180 a = 150 Initial quantity of water in the mixture = 1.2 × 150 = 180 ml
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