What is the total initial quantity of the mixture if it originally had petrol and diesel in an 8:7 ratio, and after removing 315 ml of the mixture and adding 52 ml of diesel and 88 ml of petrol to the remaining mixture, the ratio of petrol to diesel became 4:3?
We can say that quantity of petrol and diesel in the mixture initially is '8p' ml and '7p' ml. Quantity of petrol in 315 ml of mixture = (8/15) × 315 = 168 ml Quantity of diesel in 315 ml of mixture = 315 – 168 = 147 ml According to question; (8p – 168 + 88)/(7p – 147 + 52) = 4/3 (8p – 80)/(7p – 95) = 4/3 6p – 60 = 7p – 95 p = 35 Quantity of initial mixture = 15 × 35 = 525 ml
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