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ATQ, Quantity of petrol in the mixture initially = 210 × (3/5) = 126 liters Quantity of diesel in the mixture initially = 210 × (2/5) = 84 liters According to the question, (126 + p):(84 + 1.5p) = 5:4 504 + 4p = 7.5p + 420 84 = 3.5p p = 24 Quantity of petrol that is added = 24 liters Quantity of diesel that is added = 36 liters Hence Required quantity = 24 + 36 = 60 liters
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