Question
In a total 80-liter mixture of milk and water, there is
25% milk. How many liters of water should be added so that the quantity of milk in the mixture becomes 16%?Solution
Total mixture of milk and water = 80 milk = 80×25/100 = 20 liter then water will be = 80-20= 60liter ATQ- x × 16/100 = 20 x = 125 water should be added = 125 - 80 = 45liter
I. 8a2 – 22a+ 15 = 0
II. 12b2 - 47b + 40=0
I. 2x2 – 5x – 12 = 0
II. 2y2 + 13y + 20 = 0
For 3x² − 10x − 8 = 0, find (1/α + 1/β).
I. x2Â - 9x - 52 = 0
II. y2Â - 16y + 63 = 0
I. 10x2 + 33x + 9 = 0
II. 2y2 + 13y + 21 = 0
I. 3x2 - 16x - 12 = 0
II. 2y2 + 11y + 9 = 0
I. 2y² - 11 y + 15 = 0
II. 2x² + 3x – 14 = 0
I). 5p2 Â - p - 4 = 0
II). q2 - 12q + 27 = 0
If the roots of the quadratic equation 5x² + 4x + 6 = 0 are α and β, then what is the value of [(1/α) + (1/β)]?
...I. y/16 = 4/yÂ
II. x3 = (2 ÷ 50) × (2500 ÷ 50) × 42 × (192 ÷ 12)