15 liters are drawn from a cask full of wine and then filled with water. This operation is performed two more times. The ratio of the quantity of wine now left in the cask to that of the water is 8:27. How much wine did the cask hold originally
Let the quantity of the wine in the cask originally be x liters. Then, quantity of wine left in cask after 3 operations = [x {1 - (15/x)}3] liters Therefore, [x {1 - (15/x)}3 /x] = 8/27 [1 - (15/x)}2] = (2/3)3 x = 45 The original quantity of cask = 45 liters
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