A mixture consisting of 360 liters contains petrol and diesel in a ratio of 5:4, respectively. After removing 7.5% of the mixture and replacing it with an equal quantity of diesel, determine the final ratio of the quantity of petrol to that of diesel in the mixture.
ATQ, Quantity of petrol in 360 litres of mixture = (5/9) × 360 = 200 litres So, quantity of diesel in 360 litres of mixture = 360 – 200 = 160 litres Quantity of mixture taken out = 0.075 × 360 = 27 litres Quantity of petrol in 27 litres of mixture = (5/9) × 27 = 15 litres So, quantity of diesel in 27 litres of mixture = 27 – 15 = 12 litres Therefore, required ratio = (200 – 15):(160 – 12 + 27) = 185:175 = 37:35
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