Question
In a container containing 120 liters of pure petrol, 40
liters of petrol are drawn and replaced with the same quantity of diesel. This process is repeated twice more. Determine the approximate quantity of petrol remaining in the container.Solution
ATQ, Quantity of petrol left in the container = y{1 – (a/y)}n Where, y = original quantity of petrol, a = quantity of petrol replaced and n = number of times the process is repeated. Therefore, quantity of petrol left in the container = 120{1 – (40/120)}3 = 35.55 ~ 35.5 litres
38, 41, 50, ?, 158, 401Â
15.975 ×27.825 + (76.01)² + 12.98×18.426 = ?+ (79.09)²
Find the missing term in the series:
2, 7, 22, 67, 202, ?
13    13      26       ?      832       13312
...100, 120, 260, ?, 3220, 16120
0, 6, 24, ?, 120, 210
What will come in place of the question mark (?) in the following series?
50, 70, 110, 190, 310, ?
8      27       64      125     ?       343Â
...- What will come in place of (?) in the given number series.
3, 9, 15, 21, ?, 33 What value should come in the place of (?) in the following number series?
?, 664, 706, 769, 853, 958
