Question
What is the original amount of mixture 'P' if 25% of it,
consisting of petrol and diesel in a 5:6 ratio, is combined with 240 liters of mixture 'Q' with a petrol and diesel ratio of 5:3, resulting in a final mixture 'Q' with a petrol to diesel ratio of 4:3?Solution
ATQ, Let the initial quantity of petrol and diesel in mixture ‘P’ be 5p litres and 6p litres, respectively Quantity of petrol in mixture ‘Q’ = 240 × (5/8) = 150 litres Quantity of diesel in mixture ‘Q’ = 240 – 150 = 90 litres ATQ, (150 + 0.25 × 5p)/(90 + 0.25 × 6p) = 4/3 Or, 450 + 3.75p = 360 + 6p Or, 2.25p = 90 Or, p = 90/2.25 = 40 Therefore, total quantity of mixture ‘Q’ = 5p + 6p = 440 litres
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