55% of the original 'a' liters of pure petrol is taken out from a container and replaced with 66 liters of Methanol, ensuring the total quantity of the mixture remains constant. Determine the ratio of petrol to Methanol in the resulting mixture 'M,' which initially contains (0.75a + 10) liters of petrol and '2a' liters of Methanol.
ATQ, Total quantity of mixture = a = 66/0.55 = 120 litres Therefore, quantity of petrol in mixture ‘M’ = (0.75a + 10) = 0.75 × 120 + 10 = 90 + 10 = 100 litres Quantity of Methanol in mixture ‘M’ = 2a = 240 litres Required ratio = 100:240 = 5:12
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