ATQ, Let the initial quantity of oil in the mixture be 100a litres Therefore, initial quantity of diesel in the mixture = 0.8 × 100a = 80a litres Ratio of quantity of oil to that of diesel = 100a:80a = 5:4 Therefore, p:q must be equal to 5:4 such that ratio of oil to diesel in the resultant mixture remains same. For I: (p:q) = 25:20 = 5:4 Therefore, I is possible. For II: (p:q) = 30:18 = 5:3 Therefore, II is not possible For III: (p:q) = 10:12 = 5:6 Therefore, III is not possible.
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