A certain quantity of a 35% sugar solution is mixed with 10 liters of a 48% sugar solution to obtain a 40% sugar solution. How many liters of the 35% sugar solution were in the mixture?
Let Q liters of a 35% sugar solution be mixed with 10 liters of a 48% sugar solution to obtain 40% sugar. In Q liters, the quantity of sugar = Q × 35% = 0.35Q liters In 8 liters, the quantity of sugar = 10× 48% = 10 × 0.48 = 4.80 liters According to the question, 0.35Q + 4.8 = (10 + Q) × 40% 0.35Q + 4.8 = (10 + Q) × 0.4 0.35Q + 4.8 = 4 + 0.4Q 0.4Q - 0.35Q = 4.8 - 4 0.05Q = 0.8 Q=.8/.05 Q=16 liters
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