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ATQ, Let the quantity of cola and water in the initial mixture be '3u' liters and '2u' liters, respectively. Quantity of cola in 40 liters of the mixture = 40 x (3/5) = 24 liters. Quantity of water in 40 liters of the mixture = 40 - 24 = 16 liters. According to the question, (3u - 24) = (2u - 16 + 10) + 18 Or, 3u - 2u = 24 - 16 + 10 + 18 Or, u = 36 Initial quantity of the mixture = 5u = 5 x 36 = 180 liters.
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