ATQ, Original amounts: Milk = 120 liters Water = x liters 25% removed: Milk removed = 0.25 × 120 = 30 liters Water removed = 0.25 × x = 0.25x liters Remaining: Milk remaining = 120 - 30 = 90 liters Water remaining = x - 0.25x = 0.75x liters Adding water: Final water = 0.75x + 10 liters Equal amounts: 90 = 0.75x + 10 Solving for 'x': 0.75x = 90 - 10 0.75x = 80 x = 80 / 0.75 ≈ 106.67 liters or 107 liters
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