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    Question

    In a 600 ml mixture of alcohol and water, the ratio of

    alcohol to water is 3:2. If 200 ml of the mixture is removed and replaced with 50 ml of water, what is the difference between the quantity of water and alcohol in the final mixture?
    A 25 ml Correct Answer Incorrect Answer
    B 30 ml Correct Answer Incorrect Answer
    C 45 ml Correct Answer Incorrect Answer
    D 65 ml Correct Answer Incorrect Answer
    E none of these Correct Answer Incorrect Answer

    Solution

    ATQ, Initial quantity of alcohol: 600 × 3/5 = 360 ml Initial quantity of water:  600−360=240 Quantity of alcohol removed: 200 × 3/5 = 120 ml Quantity of water removed:  200−120=80 ml Alcohol left after removal:  360−120=240 ml Water left after removal: 240−80=160 ml Final quantity of water: 160+50=210 ml Required difference: 240−210=30 ml

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