Question
A 200 litres mixture of juice and water contains 30%
juice. How much water should be added to the mixture to make the quantity of water 80% of the total mixture?Solution
ATQ, Initial quantity of juice in the mixture = 0.3 Γ 200 = 60 litres Initial quantity of water = 200 β 60 = 140 litres Let the quantity of water added be βxβ litres According to the question, (140 + x) = 0.8(140 + x + 60) Or, 140 + x = 160 + 0.8x Or, x = 20/0.2 = 100 Therefore, the quantity of water to be added = 100 litres
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