Three mixtures: A, B, and C containing 35%, 55%, and X% of water, respectively. If all these mixtures are mixed in the ratio of 2:2:1 to form a resultant mixture, and the resultant mixture contains 40% of water in it, then find the value of X.
ATQ, Let the quantity of mixture A, B, and C mixed be 200 litres, 200 litres, and 100 litres, respectively. Quantity of water in mixture A, B, and C is 70 litres, 110 litres, and X litres, respectively. According to the question, (70 + 110 + X)/500 = 40/100 180 + X = 200 X = 20
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