if 70 liters of milk solution contains 60% milk, how much milk should be added to make the solution 80% milk?
Current Milk in Solution= 60% of 70 liters = 42 liters of milk. Let x be the amount of milk to add- New total solution volume = 70+ x liters. New milk amount = 42+ x liters. ATQ- (42+x)/(70+x) =0.80 42+x =0.80 (70+x) 42+x =56+.80x .20x =14 =14/.20 x =70 liters.
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